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# Reasoning Questions For DSSSB Exam: 19th June 2018 (Solutions)

Directions (1-2): Find the missing term in the following number series.

Q1. 12, 8, 14, 6, 16, ?
(a) 18
(b) 32
(c) 5
(d) 4
Q2. 1, 6, 13, 22, 33, ?
(a) 47
(b) 43
(c) 46
(d) 44
Q3. Anu is 300 days older than Varun and Sandeep is 50 weeks older than Anu. If Sandeep was born on Tuesday, on which day was Varun born?
(a) Monday
(b) Thursday
(c) Tuesday
(d) Friday

Q4. From the given alternatives, select the word which can be formed using the letters of the given word.
IMMEASURABLE
(a) BAILABLE
(b) BLUE
(c) MEAT
(d) BIBLE
Q5. In a code language ‘FORGE’ is written as ‘FPTJI’; how should ‘CULPRIT’ be written in the same code?
(a) CVNSVNZ
(b) CSJNPGR
(c) CVMQSTU
(d) CXOSULW
(a) SLPHO
(b) SHLPO
(c) SLOPH
(d) QAZTT
Q7. If 2 × 16 = 8; 8 × 8 = 1; 6 × 12 = 2, then 12 × 144 = ?
(a) 11
(b) 12
(c) 16
(d) 24

Q8. Some equations are solved on the basis of a certain system. Using the same, solve the unsolved equation.
If 10 – 3 = 12, 12 – 4 = 13, 14 – 5 = 14, then 16 – 6 = ?
(a) 10
(b) 15
(c) 16
(d) 18
Directions (9-10): In each of the following questions, select the missing number from the given responses.
Solutions

Sol 2. Ans.(c)
Sol. 1 + 5 = 6
6 + 7 = 13
13 + 9 = 22
22 + 11 = 33
33 + 13 = 46

Sol 3. Ans.(a)
Sol. 50 weeks = 50 × 7 = 350 days
Anu is 300 days older than Varun.
Sandeep is 350 days older than Anu.
Sandeep is (350 + 300) days older than Varun.
Sandeep was born on Tuesday.
650 days = 650/7 = 92 weeks 6 days
Number of odd days = 6
So, Varun was born 6 days after Tuesday, i.e., Monday.

Sol 4. Ans.(b)
Sol. There is only one ‘B’ in the given word. So, the words BAILABLE and BIBLE cannot be formed.
There is no ‘T’ letter in the given word. So, the word MEAT cannot be formed.

Sol 7. Ans.(b)
Sol. 2 × 16 = 8
⇒16/2=8
8 × 8 = 1
⇒8/8=1
6 ×12 = 2
⇒12/6=2
Therefore,
12 × 144 = ?
⇒?=144/12=12

Sol 8. Ans.(b)
Sol. 10 – 3 = 12
⇒ 10 – 3 = 7 and 7 + 5 = 12
12 – 4 = 13
⇒ 12 – 4 = 8 and 8 + 5 = 13
14 – 5 = 14
⇒ 14 – 5 = 9 and 9 + 5 = 14
Similarly,
16 – 6 = ?
⇒ 16 – 6 = 10 and 10 + 5 = 15

Sol 9. Ans.(b)
Sol. First column
(1 + 2 + 4 + 3) × 5
= 10 × 5 = 50
Second column
(3 + 4 + 5 + 2) × 5
= 14 × 5 = 70
Third column
? = (7 + 4 + 9 + 3) × 5
⇒ ? = 23 × 5 = 115

Sol 10. Ans.(a)
Sol. The sum of all the three numbers in each column is 40.
First column
13 + 11 + 16 = 40
Second column
9 + ? + 20 = 40
⇒ ? = 40 – 29 = 11
Third column
24 + 6 + 10 = 40