Mathematics Questions For All Teaching Exams: 24th July 2019 (Solutions)_00.1
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Mathematics Questions For All Teaching Exams: 24th July 2019 (Solutions)

Mathematics Questions For All Teaching Exams: 24th July 2019 (Solutions)_40.1

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2019DSSSB ,KVS,STET Exam.

Q1. Find the number that is as much greater than 49 as is less than 95.
वह संख्या ज्ञात करें जो 49 उतना ही अधिक है जितना वह 95 से कम है
(a) 23
(b) 55
(c) 72
(d) 76

Q2. Tanzeem spent 1/5 of his salary on his friends, 1/10 of his salary on accommodation and 1/4 of his salary on savings. If he has Rs. 1800 left in his wallet, then find his total expenditure on accommodation and savings.
तन्ज़ीम अपने वेतन का 1/5 हिस्सा अपने दोस्तों पर, अपने वेतन का 1/10 आवास पर और अपने वेतन का 1/4 हिस्सा बचत पर व्यय करता है. यदि उसके वॉलेट में 1800 रूपये हैं, तो आवास और बचत पर उसका कुल व्यय ज्ञात कीजिये:
(a) Rs. 1,200
(b) Rs. 1,400
(c) Rs. 1,600
(d) Rs. 1,800
Mathematics Questions For All Teaching Exams: 24th July 2019 (Solutions)_50.1
Mathematics Questions For All Teaching Exams: 24th July 2019 (Solutions)_60.1
Q5. The point at which the perpendicular bisectors of the sides of a triangle intersect is known as _____________________.
बिंदु जिस पर एक त्रिभुज की भुजाओं के लंबवत द्विभाजक एक दूसरे को काटते हैं उन्हें _______ कहा जाता है.
(a) circum-centre/ परिकेन्द्र
(b) orthocenter/ऑर्थो केंद्र
(c) centroid/केंद्रक
(d) in-center/अंत: केंद्र

Q6. The radius of the circle circumscribing the three vertices of an equilateral triangle is 12 cm. Determine the height (in cm) of the equilateral triangle.
एक समभुज त्रिभुज के तीनों कोनो को घेरने वाले वृत्त की त्रिज्या 12से.मी है. समभुज त्रिभुज की ऊंचाई (से.मी में) ज्ञात कीजिये? 
(a) 12
(b) 14
(c) 18
(d) 20

Q7. If P = 350 and Q = 600, then P is how much percentage less than Q?
यदि P = 350 और Q = 600, तो P,Q से कितने प्रतिशत कम है? 
(a) 41.66
(b) 58.33
(c) 71.42
(d) 35.33

Q8. The ratio of two numbers is 5 : 4. If the sum of both the numbers is 180, then what is the smaller number among both the numbers?
दो संख्याओं का अनुपात 5:4 है। यदि दोनों संख्याओं का योग 180 है, तो दोनों संख्याओं में से छोटी संख्या कौन-सी है? 
(a) 100
(b) 80
(c) 60
(d) 75

Q9. P started a business by the investing Rs 35000 and Q joined him after one year with an amount of Rs 21000. After two years from the starting of the business, they earned profit of Rs 26000. What will be the P’s share (in Rs) in the profit?
P, 35000रू के निवेश द्वारा एक व्यापार की शुरुआत करता है और Q, 21000रूपए की राशि के साथ एक वर्ष बाद उससे जुड़ता है। व्यापार की शुरुआत से दो वर्ष बाद वे 26000रूपए का लाभ अर्जित करते हैं। लाभ में P का हिस्सा (रूपए में) कितना होगा?   
(a) 15000
(b) 18000
(c) 20000
(d) 16000
Q10. If 31x + 31y = 403, then what is the average of x and y?
यदि 31x + 31y = 403, तो x और y का औसत क्या है?
(a) 3.5
(b) 5
(c) 6.5
(d) 13
Solutions:
S1. Ans.(c)
Sol.
Let the required number = x 
ATQ,
x – 49 = 95 – x 
2x = 144 
x = 72 
S2. Ans.(b)
Sol.
We have, F = A + S = 1/5+1/10+1/4=11/20  
Remaining Rs. in his wallet = 9/20=1800
1 = 4000
A + S = 1/10+1/4=4000×7/20= Rs. 1400
S3. Ans.(a)
Sol.
We have, z² + 2 = 2z
z² – 2z = – 2
∴ (2–2z + z²) (2 + 2z – z²) = 
(2–2) (2 + 2z – z²) = 0
Mathematics Questions For All Teaching Exams: 24th July 2019 (Solutions)_70.1
S5. Ans.(a)
Sol.
Point of intersection of perpendicular bisectors of a triangle is known as circumcenter.  
S6. Ans.(c)
Sol.
We have, (side )/√3=12 ⇒ Side = 12√3
Height of an equilateral triangle = √3/2× side = √3/2×12√3 = 18 cm    
S7. Ans.(a)
Sol.
We have, P = 350 & Q = 600 
Req. percentage = (600-350)/600=250/600×100
= 41.66%
S8. Ans.(b)
Sol.
Let the numbers are 5x & 4x.
ATQ,   
5x + 4x = 180
9x = 180
x = 20
Smaller number = 4x = 4 × 20 = 80 
S9. Ans.(c)
Sol.
Profit Ratio = Investment × time
Profit Ratio = 35000 × 2 : 21000 × 1 
= 10: 3
We have 13 unit = 26000
P’s share = 10 unit = 26000/13×10 = 20,000 Rs.
S10. Ans.(c)
Sol.
We have, 31x + 31y = 403 
⇒ x + y = 13 
Avg of x & y = (x+y)/2 = 13/2 = 6.5.
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