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Important Geometry Questions for UPTET 2019 | 21st December 2019

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UPTET Exam Practice Mathematics Questions

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e Mathematics“.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. With a proper system, Study Notes, Quizzes, Vocabulary one can quiet his/her nerves and exceed expectations in the blink of an eye. So, for this, we are providing you the daily quiz for all teaching exams i.e TET Exam 2019DSSSBKVSSTET Exam.

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Q5. If two complementary angles are in ratio 4:5, then angle will be
यदि दो पूरक कोण 4: 5 के अनुपात में हैं, तो कोण होगा
(a) 36°, 54°
(b) 108°, 72°
(c) 30°, 60°
(d) 40°, 50°

Q6. ABCD is a rhombus. If ∠ACB=45°, then ∠ADB is
ABCD एक समचतुर्भुज है. यदि ∠ACB=45°, तो ∠ADB होगा:
(a) 30°
(b) 60°
(c) 120°
(d) 45°

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Q8. In the figure, If AB=10 cm, CD=24 cm and distance between AB and CD is 17 cm then the radius of circle is
आकृति में, यदि AB = 10 सेमी, CD = 24 सेमी और AB और CD के बीच की दूरी 17 सेमी है, तो वृत्त की त्रिज्या है:
(a) 10 cm
(b) 12 cm
(c) 11 cm
(d) 13 cm

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Q10. Any cyclic parallelogram is:
कोई भी चक्रीय समांतर चतुर्भुज है:
(a) Rhombus/समचतुर्भुज
(b) Square/ वर्ग
(c) Rectangle/ आयत
(d) Trapezium/ समलंब



Solutions

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S2. Ans.(b)
Sol. 80°+x+60°= 180°
140°+x= 180°
X= 180°-140°
= 40°

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S7. Ans.(a)
Sol. ∠OAC= ∠ACO (OA=OC radius of circle)
40°= ∠ACO – (1)
∠OBC= ∠BCO (BO=OC radius of circle)
20° = ∠BCO – (2)
So, ∠ACB = ∠ACO+∠BCO
= 40+20= 60°
∠AOB= 2∠ACB
= 2×60°
= 120°

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S10. Ans.(c)


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