
Q1. Town D is 12 km towards the north of town A. town C is 15 km towards the west of town D. town B is 15 km towards the west of town A. how far and in which direction is town B from C?
(a) 15 km towards north
(b) 12 km towards north
(c) 3 km towards south
(d) 12 km towards south
Q2. A, P, R, X, S and Z are sitting in a row. S and Z are in the centre. A and P are at the ends. R is sitting to the left of A. who is to the right of P?
(a) S
(b) X
(c) Z
(d) None of the above
Q3. It was Wednesday on 15 August 2012. What should be the day on November 15, 2013?
(a) Wednesday
(b) Thursday
(c) Friday
(d) None of the above
Q4. How many numbers are there between 1 and 100 that are not divisible by 3 and 5?
(a) 47
(b) 43
(c) 53
(d) 58
Q5. If 40% of the people red newspaper X, 50% read newspaper Y, and 10% read both the papers, then what percentage of the people read neither of the newspaper?
(a) 10%
(b) 15%
(c) 25%
(d) 20%
Q6. Which of the following diagrams indicate the best relation between mercury, zinc and metal?
Questions (7-10): study the diagram given below and answer each of the following questions.
Q7. How many doctors are neither artists nor players?
(a) 17
(b) 5
(c) 10
(d) 30
Q8. How many doctors are both players and artists?
(a) 22
(b) 8
(c) 3
(d) 30
Q9. How many artists are players?
(a) 5
(b) 8
(c) 25
(d) 16
Q10. How many artists are neither players nor doctors?
(a) 10
(b) 17
(c) 30
(d) 15
S1. Ans. (d)
Sol.
S2. Ans. (b)
Sol.
The seating arrangement is as follows:
• • • • • •
P X S Z R A
Therefore, the right of P and X.
S3. Ans. (c)
Sol.
From August 15, 2012, till August 15, 2013, there is one extra day. In the rest of 16 days of August, there are 2 odd days. In September, there are 2 odd days, and in October, 3 odd days. In first 15 days of November, there will be 1 odd day. Thus, the total number of odd days is 1 + 2 + 2 + 3 + 1 = 9; it means 2 extra (odd) days. Hence, November 15, 2013 was Friday.
S4. Ans. (c)
Sol.
Let us draw a Venn diagram with the information given in the question.
Numbers divisible by 3 (3, 6, 9 and so on) = 33
Numbers divisible by 5 (5, 10, 15 and so on) = 20
Numbers which are divisible by both 3 and 5(15, 30, 45, 60, 75 and 90) = 6
Numbers divisible by 3 or 5 or both 3 and 5 = 27+6+14 =47 (alternatively, 33+20-6=47)
Numbers neither divisible by 3 nor by 5 = 100-47 = 53
S5. Ans. (d)
Sol.
People studying newspaper X or Y = 40 + 50 – 10 = 80.
Hence, people studying neither X nor Y = 100 – 80 = 20
(Candidates can try to solve this question with Venn diagram also.)
S6. Ans. (b)
Sol.
Mercury is also a metal, although it exists in liquid state.
S7. Ans. (a)
Sol.
S8. Ans. (c)
Sol.
S9. Ans. (c)
Sol. 22+3=25
S10. Ans. (c)
Sol.
You may also like to read :
- Get Free Study Material For UPTET 2019: Click here
- Get Free Study Material For CTET 2019: Click here
- CTET 2019: CTET Exam Notification, Syllabus, Exam Pattern