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Reasoning Questions For DSSSB, KVS Exam: 20th october 2018

Reasoning Questions For DSSSB, KVS Exam: 20th october 2018_30.1

The reasoning is the most scoring section in any competitive exam. It also develops or nourishes our critical thinking skills as compared to other subjects. In DSSSB,KVS Exam, As a student to score well in this part, you have to start your preparation now because there is negative marking as well. The more you have prepared, the better you score.

1. The weights of 4 boxes are 80, 60, 90 and 70 kilograms. Which of the following cannot be the total weight, in kilograms, of any combination of these boxes?
(a) 300
(b) 230
(c) 220
(d) 290

2. From the given words, select the word which cannot be formed using the letters of the given word.
SANCTION

(a) STOIC
(b) TACOS
(c) STONE
(d) SONIC

3. If CHANTED is coded as ZEXKQBA, then how will MAY be coded as?
(a) XIG
(b) JXV
(c) OBI
(d) XAV

4. In a certain code language, ‘+’ represents ‘x’, ‘-‘ represents ‘+’, ‘x’ represents ‘÷’ and ‘÷’ represents ‘-‘. What is the answer to the following question?
12 x 6 ÷ 5 + 4 = ?

(a) 8
(b) -18
(c) 42
(d) 18

5. If 75$26 = 4, 69$53 = 7 then what is the value of 82$46 = ?
(a) 62
(b) 56
(c) 0
(d) 91

6. A woman in a shopping complex walks 150 m East, then she turns North and walks 180 m, then she turns West and walks 70 m, then she turns to her left and walks 180 m. Where is she now with reference to her starting position?
(a) 80 m West
(b) 220 m East
(c) 80 m East
(d) 220 m West

7. In the question two statements are given, followed by two conclusions, I and II. You have to consider the statements to be true even if it seems to be at variance from commonly known facts. You have to decide which of the given conclusions, if any, follows from the given statements.
Statement 1 : Some wild are carnivores.
Statement 2 : All wild are lions.
Conclusion I : All carnivores are lions.
Conclusion II : Some lions are carnivores.

(a) Only conclusion I follows
(b) Only conclusion II follows
(c) Both I and II follow
(d) Neither I nor II follows

8. In a row, there are 6 boys between A and B and A being the first boy in row. There are 3 boys between B and C. If there are 12 boys after C, then how many maximum boys are there in the row?
(a) 20
(b) 16
(c) 24
(d) 18

9. A series is given with one term missing. Select the correct alternative from the given ones that will complete the series.
PNR, RQV, TTZ, ?, XZH
(a) VWB
(b) UXC
(c) VWD
(d) UXE

10. Six year ago Parvez’s age was same as the present age of Manish. If the present age of Parvez is one-fourth more than that of Manish’s present age, then in how many years will Parvez’s age become double of Manish’s present age?
(a) 6
(b) 12
(c) 15
(d) 18

SOLUTIONS

1. (d); 90 + 70 + 60 = 220 kg
90 + 70 + 60 + 80 = 300 kg
80 + 90 + 60 = 230 kg

2. (c); There is no ‘E’ in the given word.

3. (b); –3 series

4. (b); 12 × 6 ÷ 5 + 4 = 12 ÷ 6 – 5 × 4 = 2 – 20 = –18

5. (c); (7 + 5) – (2 + 6) = 4
(6 + 9) – (5 + 3) = 7
(8 + 2) – (4 + 6) = 0

6. (c);


7. (b);

8. (c);

∴ Maximum boys in the row = 6 + 3 + 12 + 1 + 1 + 1
= 24

9. (c); +2, +3, +4 series

10. (d); Let present age of Parvez be P and Manish be M
A.T.Q ⇒ P – 6 = M ⇒ P – M = 6 … (i)
& P=1/4 M+M ⇒ P=5M/4 …(ii)
Now from eqn. (i) and (ii)
5M/4–M=6
M = 24
∴ P = 30
∴ After 18 years, age of Parvez = 48, which is double of Manish’s present age.