Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e “Mathematics”.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. So, for this, we are providing you the daily quiz for all teaching exams i.e CTET Exam 2018, DSSSB Exam & STET Exam.
Q1. Which of the following pairs is complementary angles?
(a) 47° and 46°
(b) 43° and 37°
(c) 72° and 18°
(d) 53° and 47°
Q2. Find x in the given figure
Q3. A polygon has a perimeter of 16 cm and an area of 16 cm². The shape of the polygon is a
(d) rectangle which is not a square
Q4. In the given figure, PS = SQ = SR and ∠SPQ = 54°. Find the measure of ∠x.
Q5. A polyhedron has 7 faces and 10 vertices. How many edges does it have?
Q6. A polyhedron has 8 faces and 12 vertices. How many edges does it have?
Q7. In ∆ABC and ∆DEF, if AB = EF, BC = DE and CA = DF, then
(a) ∆ABC ≅ ∆DEF
(b) ∆ABC ≅ ∆EDF
(c) ∆ABC ≅ ∆FED
(d) ∆ABC ≅ ∆FDE
Q8. In ∆ABC and ∆LMN, AB = LM, AC = LN and ∠B = ∠M. Then the
(a) triangles cannot be congruent
(b) triangles must be congruent
(c) triangles will be congruent if ∠B is a right angle
(d) triangles are congruent only if AB = AC
Q9. The angle between the bisectors of two angles of a rectangle is
Q10. The number of vertices in a polyhedron which has 30 edges and 12 faces is
Sol. Two angles are complementary if they add up to 90 degrees.
72° + 18° = 90°
Sol. 60° + x = 145° (the exterior angle theorem)
⇒ x = 145° – 60° = 85°