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CSIR NET Notification 2022 Out: CSIR NET Notification PDF

CSIR NET Notification 2022: CSIR NET Notification 2022 has been released by National Testing Agency (NTA) on their official website. CSIR UGC NET is a test being conducted to determine the eligibility of Indian nationals for Junior Research Fellowship (JRF) and for Lectureship (LS) /Assistant Professor in Indian universities and colleges. The application process for CSIR UGC NET 2022 exam has been filled till 10 August 2022 through the official website. Today is the last day to apply online for CSIR UGC NET Exam. The exam date of CSIR UGC NET will be out soon on the official website. All the interested candidates can check CSIR UGC NET Exam eligibility criteria, syllabus, and exam pattern here.

CSIR UGC NET Notification 2022

The CSIR UGC NET exam is conducted twice a year to determine the eligibility of the candidates appearing for the post of Assistant Professor. The Candidates qualifying for the Junior Research Fellowship (JRF) will be awarded a stipend and other benefits while pursuing their PhD course.

The candidates who will qualify for the exam will become eligible to apply for PhD and/or post of Assistant Professor in various Universities and colleges in India. The mode of examination is online i.e. the eligibility test will be conducted as Computer Based Test (CBT) only.

 

CSIR UGC NET Notification 2022: Overview

The CSIR NET Exam is conducted by the National Testing Agency. The exam is conducted twice a year. Based on the tweet announcing the official CSIR NET exam date, NTA will conduct two more CSIR UGC NET Exams in 2022. To know more about the CSIR NET Notification, candidates can go through the following table:

Name of Examination CSIR NET (Council of Science and Industrial Research Nationals Eligibility Test)
Conducting Body Council of Science and Industrial Research & National Testing Agency
Exam Level National
Frequency of Exam Twice a year
Mode of Examination Online
Exam Shifts Shift I – 09:00 am to 12:00 noon
Shift II- 03:00 pm to 06:00 pm
Duration of Examination 180 minutes
Official Website https://csirnet.nta.nic.in/

CSIR NET Notification 2022: Important Dates

The candidates should always stay updated about the important dates and events to avoid the disappointment of missing dates. Keep an eye on the following table to never miss any important date related to the CSIR NET Notification.

Events Date
Release Date of Notification 11 July 2022
Online Application Form Started 11 July 2022
Online Application Form Closed 10 August 2022
Correction Window Open 12- 16 August 2022
CSIR NET Admit Card 2022 It will be Updated Soon
 CSIR NET Exam Date 2022 It will be Updated Soon

CSIR UGC NET Notification 2022 PDF

The official CSIR NET Notification 2022 has been released on the official website. The following given a direct link to the official CSIR NET Notification PDF has been active till 10 Aug 2022. Candidates are advised to keep monitoring this article to stay updated on the CSIR NET Notification 2022 PDF.

Download CSIR NET Official Notification PDF

CSIR NET Notification 2022: Steps To Apply For CSIR UGC NET Exam

  • Step 1 : Visit the Official Website of the CSIR UGC NET exam i.ehttps://csirnet.nta.nic.in/
  • Step 2 : Register for Online Form submission using a unique Email ID and Mobile No.
  • Step 3: Fill in the Online Application Form and note down the system generated
    Application No.
  • Step 4 : Upload legible scanned images of:
Document Size
candidate photograph
  • in jpg/ jpeg file,
  • 10KB – 200KB
  • either in colour or black & white with 80% face (without mask) visible including ears against white background
candidate’s signature 4KB – 30KB
Duly verified Result Awaited Attestation Form 50KB to 500KB
Category Certificate, if applicable (SC/ ST/OBC/ EWS etc.) 50KB to 300KB
PwD Certificate, if applicable 50KB to 300KB
  • Step 5: Pay the prescribed fee through Net Banking / Debit Card / Credit Card and UPI, and keep proof of fee paid for future reference.
  • Step 6: Download, save and print copies of the Confirmation Page after successful fee payment for future reference.

Direct Link To Apply CSIR UGC NET Application Form 2022

The direct link to apply for CSIR UGC NET online application has been given below. All the eligible candidates can apply online till 10 August 2022 for the CSIR UGC NET form. Candidates have to fill their personal details for the registration form.

Direct Link To Apply CSIR UGC NET Application Form

CSIR NET Notification 2022 Eligibility Criteria

The minimum eligibility criteria to appear in the CSIR NET exam for the candidates is mentioned below:

  • General / General-EWS and OBC category candidates should have a degree in M.Sc. or equivalent degree/ Integrated BS-MS/ BS-4 years/ BE/ B. Tech/ B. Pharma/ MBBS with a minimum of 55% marks.
  • B.E./ B.S./ B.Tech./ B.Pharma/ MBBS final year/result awaited candidates are eligible to apply for fellowship only
  • For the SC/ ST/ PwD/Third gender candidates, there is a relaxation of 5%.

CSIR NET Notification 2022: Age limit

All the candidates should check the age limit mentioned below before applying for the CSIR UGC NET exam 2022. The age limit prescribed for the candidates appearing for the CSIR UGC NET Exam is:

  • To apply for JRF, candidates must be at least 28 years old.
  • There is no upper age limit to apply for the post of Lecturer.

CSIR NET Notification 2022: Application Fees

Candidates waiting to fill up the CSIR UGC NET Application form 2022 should check out the fees application fees properly. In the following, the CSIR UGC NET Application fees are mentioned below.

Category Fees
General/General-EWS Rs. 1000/-
OBC-NCL* Rs. 500/-
SC/ST Rs. 250/-
Third Gender Rs. 250/-
PwD NIL

CSIR UGC NET Notification 2022: Exam Pattern

The candidates should go through the exam pattern properly before starting their preparation for the CSIR UGC NET Exam 2022. The candidates should remember that the CSIR UGC NET exam 2022 will have a negative marking. The other salient features of the CSIR NET exam pattern 2022 are mentioned below:

  • Duration of Exam: 3 hours
  • Exam Type:  Objective Type, Multiple-Choice Questions.
  • There will be no break between papers.
  • The Test will consist of three parts i.e. Part A, Part B, and Part C.
  • Mode of Examination: Computer-Based Test (CBT) only.
  • Negative Marking – Yes (Refer to subject-wise marking scheme in tables below for clarity).

Subject Wise Scheme of Examinations and Negative Marking:

The candidate should go through the subject-wise marking scheme of the CSIR UGC NET examination 2022. Candidates should remember that there is negative marking and the negative marking scheme is explained in detail below. The marking scheme is as follows:

CHEMICAL SCIENCES Part A Part B Part C Total
Total Questions 20 40 60 120
Max Number of Questions to attempt 15 35 25 75
Marks for each correct answer 2 2 4 200
Negative marking for parts A, B & C is @
25%
0.5 0.5 1

 

EARTH, ATMOSPHERIC, OCEAN

AND PLANETARY SCIENCES

Part A Part B Part C Total
Total Questions 20 50 80 150
Max Number of Questions to attempt 15 35 25 75
Marks for each correct answer 2 2 4 200
Negative marking for parts A & B is @ 25%
and part C is @ 33%
0.5 0.5 1.32

 

LIFE SCIENCES Part A Part B Part C Total
Total Questions 20 50 75 145
Max Number of Questions to attempt 15 35 25 75
Marks for each correct answer 2 2 4 200
Negative marking for parts A, B & C is @
25%
0.5 0.5 1

 

MATHEMATICAL SCIENCES Part A Part B Part C Total
Total Questions 20 40 60 120
Max Number of Questions to attempt 15 25 20 60
Marks for each correct answer 2 3 4.75 200
Negative marking in Parts A & B is @ 25%;
no negative marking in Part C
0.5 0.75 0

 

PHYSICAL SCIENCES Part A Part B Part C Total
Total Questions 20 25 30 75
Max Number of Questions to attempt 15 20 20 55
Marks for each correct answer 2 3.5 5 200
Negative marking for parts A, B & C is @
25%
0.5 0.875 1.25

CSIR NET Notification 2022 Syllabus

The CSIR NET exam question paper is divided into three parts- Part- A, Part B, and Part C. The basic structure of the question paper for all the subjects is the same. Part-A is based on General Science, Quantitative Reasoning & Analysis, and Research Aptitude. Part-B is based on the concerned subject. Finally, Part- C is based on the Scientific concepts and/ or application of the scientific concepts. Go through the table mentioned below for clarity:

Part A Part B Part C
General aptitude like series formation, numerical ability Subject Specific Subject Specific

Direct Link to download the CSIR NET Syllabus 2022:

For a detailed syllabus, candidates can easily download the subject-wise complete syllabus pdf by clicking on the links given below.

CSIR UGC NET Notification 2022:  Examination Schedule

CSIR UGC NET 2022 examination date will be going to notified soon on their official website. The examination schedule is given below:

Dates of Examination Will be Notified soon
  First Shift Second Shift
Timing of Examination 09.00 am- 12.00 pm 03.00 pm- 6.00 pm
Duration of Examination 03 hours
Entry into the Examination Centre 7.00 am – 8.00 am 1.00 pm -2.00 pm
Entry in the Examination Hall/Room 8.15 am- 8.30 am 2.15 pm- 2.30 pm
Test Commences 9.00 am 3.00 pm
Test Concludes 12.00 pm 6.00 pm

CSIR UGC NET Notification 2022: FAQs

Q. When will the New CSIR UGC NET Exam Date  notification be released? 

A. The CSIR NET Exam notification will be released by the NTA on their official website.

Q. What is the name of the CSIR UGC NET Exam conducting body? 

A. The National Testing Agency (NTA) is the exam conducting body for the CSIR NET Exam.

Q. What is the age limit to apply for the CSIR NET Exam?

A. The lower age limit to apply for JRF is 28 years. There is no upper age limit to apply for the post of Lecturer.

Q. How many attempts are allowed for the CSIR NET Exam?

A. There is no limit set by the conducting body on the number of attempts taken by the candidates to qualify for the CSIR NET Exam.

 

Important Links
CSIR UGC NET Notification CSIR UGC NET Syllabus
CSIR UGC NET Exam Date CSIR UGC NET Online Application form

 

CSIR NET Notification 2022 Out: CSIR NET Notification PDF_40.1

 

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