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    Given that at 298.15K, EFe+3/Fe0=−0.04V;EFe+2/Fe0=−0.44V.E^0_{Fe^{+3}/Fe}=-0.04V;E^0_{Fe^{+2}/Fe}=-0.44V.EFe+3/Fe0​=−0.04V;EFe+2/Fe0​=−0.44V.​​At
    Question

    Given that at 298.15K, EFe+3/Fe0=0.04V;EFe+2/Fe0=0.44V.E^0_{Fe^{+3}/Fe}=-0.04V;E^0_{Fe^{+2}/Fe}=-0.44V.​​At this temperature, the value of  EFe+3/Fe+20E^0_{Fe^{+3}/Fe^{+2}} is

    A.

    1.24V

    B.

    1.00V

    C.

    0.40V

    D.

    0.76V

    Correct option is D

    A given reaction may be obtained from other reactions by carrying out the simple mathematical manipulations such as addition, subtraction, multiplication by a number and so on. Since G° is a state function, the ΔG° of the given reaction may be obtained by carrying out the corresponding manipulations on ΔG°s values of the reactions. This procedure, however, cannot be adopted while calculating E° of a half-cell reaction from the values of other half-cell reactions. Nevertheless, we can determine the potential of a half-cell reaction from the potentials of other half-cell reactions via the associated ΔG° values. First of all, we write

    ​for each and every half-cell reaction and then carry out the appropriate manipulations of the reactions along with the corresponding ΔG°s values to give the given half-cell reaction and its ΔG° value. Knowing the number n of electrons involved in the given reaction and the obtained value of ΔG°, the value E° may be determined. To illustrate the procedure, we compute E° for the reaction


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