hamburger menu
All Coursesall course arrow
adda247
reward-icon
adda247
    arrow
    arrow
    arrow
    For the cell Cd ∣ CdCl2 ∣∣ AgCl ∣ Ag; Ecell∘=0.675 V and dEcell∘dT=−6.5×10−4 V K−1 at 27∘C. ΔH (kJ mol−1) value for the 
    Question

    For the cell Cd CdCl2 AgCl Ag; Ecell=0.675 V and dEcelldT=6.5×104 V K1 at 27C. ΔH (kJ mol1) value for the reaction Cd+2AgCl2Ag+CdCl2 is closest to:\text{Cd} \, | \, \text{CdCl}_2 \, || \, \text{AgCl} \, | \, \text{Ag} ; \, E^\circ_{\text{cell}} = 0.675 \, \text{V} \, \text{and} \, \frac{dE^\circ_{\text{cell}}}{dT} = - 6.5 \times 10^{-4} \, \text{V K}^{-1} \, \text{at} \, 27^\circ \text{C}. \, \Delta H \, (\text{kJ mol}^{-1}) \, \text{value for the reaction} \, \text{Cd} + 2\text{AgCl} \rightarrow 2\text{Ag} + \text{CdCl}_2 \, \text{is closest to:}


    A.

    -168

    B.

    -123

    C.

    -95

    D.

    -234

    Correct option is A

    The free energy change accompanying a cell reaction can be obtained from the emf of the cell through the relation

    The changes in enthalpy and entropy of the cell reaction can also be determined if the temperature dependence of the emf of the cell is available. For this, we make use of the Gibbs-Helmholtz equation:

    Similar Questions

    test-prime-package

    Access ‘CSIR NET Chemical Sciences’ Mock Tests with

    • 60000+ Mocks and Previous Year Papers
    • Unlimited Re-Attempts
    • Personalised Report Card
    • 500% Refund on Final Selection
    • Largest Community
    students-icon
    383k+ students have already unlocked exclusive benefits with Test Prime!
    test-prime-package

    Access ‘CSIR NET Chemical Sciences’ Mock Tests with

    • 60000+ Mocks and Previous Year Papers
    • Unlimited Re-Attempts
    • Personalised Report Card
    • 500% Refund on Final Selection
    • Largest Community
    students-icon
    383k+ students have already unlocked exclusive benefits with Test Prime!
    Our Plans
    Monthsup-arrow