Daily Concept Booster Civil Engineering : Temperature stress |_00.1
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Daily Concept Booster Civil Engineering : Temperature stress

Temperature stress (σt)-

Daily Concept Booster Civil Engineering : Temperature stress |_50.1

[(Temperature increase than Length increase Temperature decrease than length decrease)]
(Change in length (∆L)=L α∆T)
α → Coefficient of thermal expansion.

Thermal strain (ϵT ) = ∆L/L
ϵT=Lα∆T/L
▭(ϵT=α∆T)
E=Stress/Strain
E=σT/(ϵT ) (prevented)
σt=E(ϵthermal )Prevented
(σt=Eα∆T)

→ Thermal stresses are developed due to change in temperature.
→ If free expansion is allowed to occur then there will be no thermal stress.
→ Thermal stresses will develop only in change in length which is prevented.

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