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When a hydrogen atom is exposed to a perturbation V=E.z, the first order correction to the wave function comes only from the orbital​
Question

When a hydrogen atom is exposed to a perturbation V=E.z, the first order correction to the wave function comes only from the orbital


A.

2s

B.

2pz

C.

3py

D.

3dz​2

Correct option is B

Many problems-and almost all the problems of interest in chemistry-do not have exact solutions. To make progress with these problems we need to develop techniques of approximation. There are two major approaches, variation theory and perturbation theory.

Time-independent perturbation theory

In perturbation theory, we suppose that the Hamiltonian for the problem we are trying to solve,

{\displaystyle {\hat {H}}}

can be expressed as the sum of a simple Hamiltonian,

{\displaystyle {\hat {H}}}

which has known eigenvalues and eigenfunctions, and a contribution,

{\displaystyle {\hat {H}}}

which represents the extent to which the true Hamiltonian differs from the ‘model’ Hamiltonian:

{\displaystyle {\hat {H}}}

In time-independent perturbation theory, the perturbation is always present and unvarying. For example, it might represent a dip in the potential energy of a particle in a box in some region along the length of the box. In time-independent perturbation theory, we suppose that the true energy of the system differs from the energy of the simple system, and that we can write

{\displaystyle {\hat {H}}}
{\displaystyle {\hat {H}}}
{\displaystyle {\hat {H}}}

The first-order correction to the energy of the ground state (with the wavefunction ψ0 and energy E0), is

{\displaystyle {\hat {H}}}
{\displaystyle {\hat {H}}}

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