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    When a hydrogen atom is exposed to a perturbation V=E.z, the first order correction to the wave function comes only from the orbital​
    Question

    When a hydrogen atom is exposed to a perturbation V=E.z, the first order correction to the wave function comes only from the orbital


    A.

    2s

    B.

    2pz

    C.

    3py

    D.

    3dz​2

    Correct option is B

    Many problems-and almost all the problems of interest in chemistry-do not have exact solutions. To make progress with these problems we need to develop techniques of approximation. There are two major approaches, variation theory and perturbation theory.

    Time-independent perturbation theory

    In perturbation theory, we suppose that the Hamiltonian for the problem we are trying to solve,

    {\displaystyle {\hat {H}}}

    can be expressed as the sum of a simple Hamiltonian,

    {\displaystyle {\hat {H}}}

    which has known eigenvalues and eigenfunctions, and a contribution,

    {\displaystyle {\hat {H}}}

    which represents the extent to which the true Hamiltonian differs from the ‘model’ Hamiltonian:

    {\displaystyle {\hat {H}}}

    In time-independent perturbation theory, the perturbation is always present and unvarying. For example, it might represent a dip in the potential energy of a particle in a box in some region along the length of the box. In time-independent perturbation theory, we suppose that the true energy of the system differs from the energy of the simple system, and that we can write

    {\displaystyle {\hat {H}}}
    {\displaystyle {\hat {H}}}
    {\displaystyle {\hat {H}}}

    The first-order correction to the energy of the ground state (with the wavefunction ψ0 and energy E0), is

    {\displaystyle {\hat {H}}}
    {\displaystyle {\hat {H}}}

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