What will be the difference in population 3 years ago and 2 years ago of a town whose current population of 2,50,000 is increasing at a rate of 25% every year?​

Correct option is D

Given:
- Current population = 2,50,000
- Growth rate = 25% per year
- We are required to find the difference in population 3 years ago and 2 years ago.

Formula Used:

Population after n years = $$P × (1 + r)^n$$​​
Where:
P = current population, r = growth rate, n = number of years

Solution:

- Population 3 years ago  $$= \frac{2,50,000 }{ (1 + 0.25)^3} = \frac{2,50,000 }{ (1.25)^3} =\frac{ 2,50,000 }{1.953125 }≈ 1,28,000$$​

- Population 2 years ago = $$\frac{2,50,000 }{(1 + 0.25)^2} = \frac{2,50,000 }{ (1.25)^2 }=\frac{ 2,50,000 }{1.5625} ≈ 1,60,000$$​

- Difference in population = 1,60,000 - 1,28,000 = 32,000