The population of a district is 383000, out of which 221000 are males. 58% of the population is literate. If 58% males are literate, then what percentage of females are literate?

Correct option is C

Given:
Total population = 38300
Males = 221000 → Females = 383000 − 221000 = 162000
58% of total population is literate
58% of males are literate
Formula Used:
Literate people = Percentage × Total / 100
Percentage = (Part / Whole) × 100
Solution:
​$$\text{Total literate people} = 58\% \text{ of } 383000 = \frac{58}{100} \times 383000 = 222140\\\ \\\text{Literate males} = 58\% \text{ of } 221000= \frac{58}{100} \times 221000 = 128180\\\ \\\text{Literate females} = \text{Total literates} - \text{Literate males}= 222140 - 128180 = 93960\\\ \\\text{Percentage of literate females}= \frac{93960}{162000} \times 100= \frac{87}{150} \times 100= 58\%$$​​
So, percentage of literate females = 58%.