$$\frac59$$​th part of the population in a village are males. If 30% of the males are married, then what percentage of the total population consists of unmarried females ?

Correct option is A

Given:
Males = $$\frac{5}{9}$$​ of total population
Married males = 30% of males
Formula Used:
Total Population = Males + Females
Percentage =$$\frac{Value}{Total}$$​ × 100
Solution:
Let the total population be 900.
Number of males = $$\frac{5}{9}$$​× 900 = 500
Number of females = 900 - 500 = 400
Number of married males = 30% of 500 = $$\frac{30}{100}$$​ × 500 = 150
Assuming monogamy, the number of married females is equal to the number of married males.
Married females = 150
Number of unmarried females = Total females - Married females
Unmarried females = 400 - 150 = 250
Percentage of unmarried females = $$\frac{250}{900} × 100$$​​
Percentage = $$\frac{250}{9} = 27\frac{7}{9}$$​​
Final Answer
So the correct answer is (a)