The current population of a town is 14,680. It increases by 25% and 70% in two successive years but decreases by 20% in the third year. What is the population of the town at the end of the third year?

Correct option is A

Given:

Present population = 14,680

1st year increase = 25%

2nd year increase = 70%

3rd year decrease = 20%

Find population at end of 3rd year.

Formula Used:

Population after change = Initial × (1 ± rate%)

​Solution:​

Changed Population = $$14680 \times \left(1 + \frac{25}{100}\right)\times \left(1 + \frac{70}{100}\right) \times \left(1 - \frac{20}{100}\right)$$ 

= 14680 × $$\frac{125}{100}\times \frac{170}{100}\times \frac{80}{100}$$ 

= $$14680 × \frac 54 \times \frac{17}{10}\times \frac{4}{5}$$​​

= 1468 × 17 

= 24956