Two years ago, the population of a city was 1,10,000. The population increased by 10% in the first year and decreased by 10% in the second year. Find the present population.

Correct option is D

Given:

Population 2 years ago = 1,10,000

1st year: Increase of 10%

2nd year: Decrease of 10%

Find present population.

Formula Used:

Population after 2 year = Original Population × $$\left(1 + \frac{increase}{100} \right) \times \left(1 - \frac{decrease}{100} \right)$$​​

Solution:

Population after 2 year ;

= 1,10,000 × $$\left(1 + \frac{10}{100} \right) \times \left(1 - \frac{10}{100} \right)$$ 

= 110000 × $$\frac{110}{100} \times \frac{90}{100}$$ 

= 108900