What will be difference in population 3 years ago and 2 years ago of a town, whose current population is 110000 and which is increasing at a rate of 25% every year?

Correct option is C

Given:

Current population = 110000

Rate of increase = 25% per annum

We are to find the difference between the population 3 years ago and 2 years ago.

Formula Used:

Population (n) years ago = Current Population $$\div \left(1 + \frac{R}{100}\right)^n$$​​

Solution:

Population 3 years ago = $$\frac{110000}{(1+\frac{25}{100})^3}$$​​

​$$= \frac{110000}{(\frac54)^3} \\ \ \\= \frac{110000 \times 64}{125} \\ \ \\ = 56320$$​​

Population 2 years ago = $$\frac{110000}{(1+\frac{25}{100})^2}$$​​

​$$= \frac{110000\times 16}{25}$$​​

= 70400

Difference = 70400 - 56320 = 14080