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What is the typical maximum sustainable yield for a fish population, given that its carrying capacity (K) is 20,000 and intrinsic growth rate (r) is 0
Question

What is the typical maximum sustainable yield for a fish population, given that its carrying capacity (K) is 20,000 and intrinsic growth rate (r) is 0.15?

A.

1,333

B.

1,500

C.

3,000

D.

6,666

Correct option is B

The Maximum Sustainable Yield (MSY) of a population occurs when the population size is at half of the carrying capacity (K). The formula for MSY is:

MSY=rK2\text{MSY} = \frac{rK}{2}

Given:

  • Carrying capacity (K) = 20,000

  • Intrinsic growth rate (r) = 0.15

   MSY =    20000×0.152\frac{20000 \times 0.15}{2} = 1500

Thus, the typical maximum sustainable yield is 1,500.

Information Booster:

  1. The Maximum Sustainable Yield (MSY) occurs at half the carrying capacity (K/2) of a population.

  2. At the MSY point, the growth rate of the population is maximized, and the population is able to maintain a sustainable yield.

  3. The MSY formula considers the intrinsic growth rate (r) and the carrying capacity (K) of the population.

Additional Knowledge:

  • 1,333 (option 1) is incorrect because it underestimates the typical MSY.

  • 3,000 (option 3) and 6,666 (option 4) are also incorrect; they overestimate the yield based on the given carrying capacity and growth rate.


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