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    What is the typical maximum sustainable yield for a fish population, given that its carrying capacity (K) is 20,000 and intrinsic growth rate (r) is 0
    Question

    What is the typical maximum sustainable yield for a fish population, given that its carrying capacity (K) is 20,000 and intrinsic growth rate (r) is 0.15?

    A.

    1,333

    B.

    1,500

    C.

    3,000

    D.

    6,666

    Correct option is B

    The Maximum Sustainable Yield (MSY) of a population occurs when the population size is at half of the carrying capacity (K). The formula for MSY is:

    MSY=rK2\text{MSY} = \frac{rK}{2}

    Given:

    • Carrying capacity (K) = 20,000

    • Intrinsic growth rate (r) = 0.15

       MSY =    20000×0.152\frac{20000 \times 0.15}{2} = 1500

    Thus, the typical maximum sustainable yield is 1,500.

    Information Booster:

    1. The Maximum Sustainable Yield (MSY) occurs at half the carrying capacity (K/2) of a population.

    2. At the MSY point, the growth rate of the population is maximized, and the population is able to maintain a sustainable yield.

    3. The MSY formula considers the intrinsic growth rate (r) and the carrying capacity (K) of the population.

    Additional Knowledge:

    • 1,333 (option 1) is incorrect because it underestimates the typical MSY.

    • 3,000 (option 3) and 6,666 (option 4) are also incorrect; they overestimate the yield based on the given carrying capacity and growth rate.


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