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    ​The diagram below depicts energy flow within a single trophic level, where I = amount ingested, NA = amount not assimilated, R = respiration, and Pn
    Question

    The diagram below depicts energy flow within a single trophic level, where I = amount ingested, NA = amount not assimilated, R = respiration, and Pn = biomass production at the trophic level.

    Which one of the following options represents correct values for Pn, NA, R and I in kcal respectively, if Pn –1 = 1000 kcal, I/Pn–1=20%, A/I=35× and Pn/A=20%?

    A.

    56, 14, 130, 200

    B.

    14, 130, 56, 200

    C.

    200, 130, 56, 14

    D.

    56, 130, 200, 14

    Correct option is B

    Explanation-

    Given -

    Pn1=1000 kcalIPn1=20%=>I=20%×1000=200 kcalAI=35%=>A=35%×200=70 kcalPnA=20%=>Pn=20%×70=14 kcalP_{n-1} = 1000\, \text{kcal} \\\frac{I}{P_{n-1}} = 20\% \Rightarrow I = 20\% \times 1000 = 200\, \text{kcal} \\\frac{A}{I} = 35\% \Rightarrow A = 35\% \times 200 = 70\, \text{kcal} \\\frac{P_n}{A} = 20\% \Rightarrow P_n = 20\% \times 70 = 14\, \text{kcal}

    Now, use the energy flow relationship:

                    A=Pn+R=>R=APn=7014=56 kcalA = P_n + R \Rightarrow R = A - P_n = 70 - 14 = 56\, \text{kcal}

    Also,       NA=IA=20070=130 kcalNA = I - A = 200 - 70 = 130\, \text{kcal}

    Final values:
    Pn = 14 kcal
    NA = 130 kcal
    R = 56 kcal
    I = 200 kcal

    Correct order: 14, 130, 56, 200 → Option b​​

                     
    ​​

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