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    The rate constant for the reaction, A2B4O→AB4 +AO is described as, log⁡k=14.1−10000 KT\log k = 14.1 - \frac{10000 \, \text{K}}{T}logk=1
    Question

    The rate constant for the reaction, A2B4O→AB4 +AO is described as, logk=14.110000 KT\log k = 14.1 - \frac{10000 \, \text{K}}{T}. The activation energy for this reaction (in kJ mol-1is closest to

    A.

    191.4

    B.

    83.14

    C.

    382.8

    D.

    166.28

    Correct option is A

    It is found experimentally for many reactions that a plot of ln k against 1/T gives a straight line. This behaviour is normally expressed mathematically by introducing two parameters, one representing the intercept and the other the slope of the straight line, and writing the Arrhenius equation​

    ​The parameter A, which corresponds to the intercept of the line at 1/T = 0, is called the pre-exponential factor or the ‘frequency factor’. The parameter Ea, which is obtained from the slope of the line

    ​is called the activation energy. Collectively the two quantities are called the Arrhenius parameters

    ​The fact that Ea is given by the slope of the plot of ln k against 1/T means that, the higher the activation energy, the stronger the temperature dependence of the rate constant (that is, the steeper the slope). A high activation energy signifies that the rate constant depends strongly on temperature. If a reaction has zero activation energy, its rate is independent of temperature. In some cases the activation energy is negative, which indicates that the rate decreases as the temperature is raised.

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