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Find the equation whose roots are (a+b)(a +\sqrt b)(a+b​)​ and (a−b)(a -\sqrt b)(a−b​) ​
Question

Find the equation whose roots are (a+b)(a +\sqrt b)​ and (ab)(a -\sqrt b) ​

A.

x² - 2ax + (a² - b) = 0

B.

x² - ax + a² - b² = 0

C.

x² + ax + a² - b² = 0

D.

x² + 2ax + (a² - b) = 0

Correct option is A

Given:
The roots of the equation are (a+b)(a +\sqrt b) and (ab)(a -\sqrt b)​​
Concept Used:
For a quadratic equation with roots r_1 and r_2​, the standard form is:
x2(Sum of roots)x+(Product of roots)=0x^2 - (\text{Sum of roots})x + (\text{Product of roots}) = 0​​
Sum of roots = r1+r2r_1 + r_2, Product of roots = r1r2r_1 \cdot r_2​ 
Solution:
Sum of roots = (a + b) + (a - b) = 2a
Product of roots = (a+b)(ab)=a2b(a +\sqrt b)(a -\sqrt b)= a^2-b​  
Substituting the sum and product into the quadratic form:
x2(Sum of roots)x+(Product of roots)=0 x22ax+(a2b)=0x^2 - (\text{Sum of roots})x + (\text{Product of roots}) = 0 \\ \ \\ \bf x^2 -2ax + (a^2 -b) = 0​​

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