Find roots of 4m² + 6m + 2 = 0

Correct option is C

Given:

Quadratic equation: 4$$m^{2} + 6m + 2 = 0.$$​​

Formula Used:
Quadratic formula m$$=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$$​, for a$$m^{2}+bm+c=0.$$​​

Solution:
Here, a = 4; b = 6; c = 2.
Discriminant: $$\Delta=b^{2}-4ac=6^{2}-4\times4\times2=36-32=4$$​​
m =$$\frac{-6\pm\sqrt{4}}{2\times4}$$​​

=$$\frac{-6\pm2}{8}$$​​
Roots:
m$$=\frac{-6+2}{8}=\frac{-4}{8}=-\frac{1}{2},$$​​

m$$=\frac{-6-2}{8}=\frac{-8}{8}=-1$$​​