Correct option is CGiven:3 (73x2−27x+14)−7(x2+8x−11)3\!\left(\frac{7}{3}x^{2}-27x+14\right)-7(x^{2}+8x-11)3(37x2−27x+14)−7(x2+8x−11) Solution: 3 (73x2−27x+14)−7(x2+8x−11) =7x2−81x+42−7x2−56x+77 =−137x+1193\!\left(\frac{7}{3}x^{2}-27x+14\right)-7(x^{2}+8x-11) \\ \ \\ = 7x^{2}-81x+42-7x^{2}-56x+77 \\ \ \\=-137x+1193(37x2−27x+14)−7(x2+8x−11) =7x2−81x+42−7x2−56x+77 =−137x+119