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    If one of the zeroes of a cubic polynomial x³ + ax² + bx + c is 1, then the product of the other two zeroes is:
    Question

    If one of the zeroes of a cubic polynomial x³ + ax² + bx + c is 1, then the product of the other two zeroes is:

    A.

    a – b – 1

    B.

    a – b + 1

    C.

    a + b + 1

    D.

    a + b – 1

    Correct option is C

    Given:

    One root is 1. Let the roots be: 1, β, γ
    We are to find the product of the other two zeroes: β × γ

    Formula used:

    Sum of roots = –a

    Sum of product of roots two at a time = b

    Solution:
    Sum of roots:
    1 + β + γ = –a
    => β + γ = –a – 1 ...(1)

    Sum of product of roots two at a time:
    1×β + βγ + γ×1 = β + γ + βγ = b ...(2)

    Substitute (1) into (2):
    (–a – 1) + βγ = b
    => βγ = b + a + 1

    Correct answer is (c)

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