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Daily Concept Booster Civil Engineering : Deflection Due to Axial load

Deflection due to axial load

Daily Concept Booster Civil Engineering : Deflection Due to Axial load |_40.1

Stress (σ)=Pinternal/A
▭(σ=P/A)
Strain (ϵ)=(change in length)/(original length)
▭(ϵ=∆L/L)

Youngs modulus of elasticity (E) =Stress/Strain
E = σ/ϵ
E=(P\/A)/(∆L\/L)
▭(∆L=PL/AE)
→ This formula is valid only when P,A,E are constant.

 

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