Daily Concept Booster Civil Engineering : Deflection Due to Axial load

Deflection due to axial load

Stress (σ)=Pinternal/A
▭(σ=P/A)
Strain (ϵ)=(change in length)/(original length)
▭(ϵ=∆L/L)

Youngs modulus of elasticity (E) =Stress/Strain
E = σ/ϵ
E=(P\/A)/(∆L\/L)
▭(∆L=PL/AE)
→ This formula is valid only when P,A,E are constant.

Boost your preparation with the all-new Concept Booster Series by Adda247 Engineering Jobs, this series aims to target all the important engineering exams such as SSC JE 2022, GATE 2022, ESE 2022, and many more. Please reach out to us with your feedback in the comment section.