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    ​X and Y together can finish work in 12 days, Y and Z can finish In 20 days and Z and X can finish in 15 days. Find in how many days X,Y and Z will fi
    Question

    X and Y together can finish work in 12 days, Y and Z can finish In 20 days and Z and X can finish in 15 days. Find in how many days

    X,Y and Z will finish the work?

    A.

    6 days

    B.

    11 days

    C.

    9 days

    D.

    10 days

    Correct option is D

    Given:

    X and Y together can finish the work in 12 days.

    Y and Z together can finish the work in 20 days.

    Z and X together can finish the work in 15 days.

    Concept Used:

    Work done together is the sum of individual work rates.

    If A and B can finish a job in tt days, then their combined work rate is \frac{1}{t} per day.

    Solution:

    Work rate of X + Y is 112\frac{1}{12} ​(since they finish the work in 12 days).

    Work rate of Y + Z is 120\frac{1}{20}​ (since they finish the work in 20 days).

    Work rate of Z + X is 115\frac{1}{15} ​(since they finish the work in 15 days).

    Let the individual work rates of X, Y, and Z be x, y, and z, respectively.

    We have the following system of equations:

    x+y=112(1) y+z=120(2) z+x=115(3)x + y = \frac{1}{12} \quad \text{(1)}\\ \ \\ y + z = \frac{1}{20} \quad \text{(2)} \\ \ \\ z + x = \frac{1}{15} \quad \text{(3)}

    Add all three equations:

    ((x+y)+(y+z)+(z+x)=112+120+115((x + y) + (y + z) + (z + x) = \frac{1}{12} + \frac{1}{20} + \frac{1}{15}

    112+120+115=560+360+460=1260=15\frac{1}{12} + \frac{1}{20} + \frac{1}{15} = \frac{5}{60} + \frac{3}{60} + \frac{4}{60} = \frac{12}{60} = \frac{1}{5}

    2(x+y+z)=152(x + y + z) = \frac{1}{5}

    x+y+z=110x + y + z = \frac{1}{10}

    The combined work rate of X, Y, and Z is 110 \frac{1}{10}​, meaning they can finish the work in 10 days.

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