Pinki, Chinki and Reema started a work and Reema left after 4 days when 46% of the work is completed and then work got completed in 9 more days. In how many days can Reema alone complete the work?

Correct option is A

Given:
Pinki, Chinki and Reema start a work together.
After 4 days, Reema leaves when 46% of the work is completed.
The remaining work is completed by Pinki and Chinki in 9 more days.
Formula Used:
Rate = Work / Time
Rate of individual = (Rate of all three) − (Rate of remaining two)
Time taken alone = Total Work / Individual Rate
Solution:
Assume total work = 100 units.
Work done in first 4 days = 46 units.
Rate of all three = 46 ÷ 4 = 11.5 units/day.
Remaining work = 100 − 46 = 54 units.
Rate of Pinki and Chinki = 54 ÷ 9 = 6 units/day.
Reema's rate = 11.5 − 6 = 5.5 units/day.
Time taken by Reema alone = 100 ÷ 5.5 = 200 ÷ 11 ≈ 18$$\frac{2}{11}$$​ days.