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A and B working together can do a piece of work in 6 days. B alone can do the same work in 14 days. How long (in days) will A alone take to do double
Question

A and B working together can do a piece of work in 6 days. B alone can do the same work in 14 days. How long (in days) will A alone take to do double the work?

A.

21

B.

22

C.

24

D.

10.5

Correct option is A

Given
Time taken by A and B together = 6 days
Time taken by B alone = 14 days
Formula Used
Total Work = LCM of days
Efficiency = Total Work / Time
Solution
Let total work be the LCM of 6 and 14, which is 42 units.
Efficiency of (A + B) =426=7 \frac{42}{6} = 7 ​units/day
Efficiency of B = 4214=3\frac{42}{14} = 3​ units/day
Efficiency of A = 7 - 3 = 4 units/day
Double the original work =42×2=84 42 \times 2 = 84 ​units
Time taken by A alone =844=21 \frac{84}{4} = 21​ days
Final Answer
So the correct answer is (a)

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