Which of the following quadratic equations satisfies that the roots are 3 and -2 ?

Correct option is C

Given:

The roots are 3 and -2 

Formula used: 

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$$ax^2 + bx + c = 0$$ 

Sum of roots = $$α+β$$ = -$$\frac{b}{a}$$ 

Product of roots = $$α⋅β$$ = $$\frac{c}{a}$$  

Solution:

$$\alpha$$ = 3 

 $$β$$ = -2

Sum of roots = 3 + (-2) = 1
​Product of roots  = $$3 \times (-2) = -6$$​

Now, 

$$(x−α)(x−β)=0$$ 

$$(x−3)(x+2)=0$$ 

$$(x ^2 +2x−3x−6)=0$$​ 

$$(x ^2 −x−6)=0$$ ,   ​

$$x ^2 −x−6=0$$ 

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