When 10% of the inhabitants of a village died of cholera, a panic set in, during which 25% of the remaining inhabitants left the village. The population then reduced to 4050. Find the number of original inhabitants.

Correct option is D

​Given:

10% died, leaving 90% of the population.

25% of the remaining left, so 75% remained.

Reduced population = 4050.

Formula Used:

​$$\text{Original Population} = \frac{\text{Reduced Population}}{(1 - \text{Death Rate}) \times (1 - \text{Left Percentage})}.$$​​

Solution: 

After 10% died  remaining 90% = 0.9 

25% leave then remaining 75% = 0.75 

Now, 

​$$\text{Original Population} = \frac{4050}{0.9 \times 0.75} = \frac{4050}{0.675} = 6000.$$​​