What is the nature of the roots of – 6 + 5 = 0?
Given:
-6 + 5 = 0
Formula Used for quadratic equation
Discriminant (D) =
Solution:
From the equation:
Putting values in Discriminant formula:
D = () - 4(3)(5)
D = 36 - 60
D = -24
If the value of D<0 : Two complex root.
So there is no real root.
Thus the correct answer is (D).
English
100 Questions
100 Marks
90 Mins English English100 Questions100 Marks90 Mins English English40 Questions30 Marks25 Mins EnglishIf one of the zeroes of a cubic polynomial x³ + ax² + bx + c is 1, then the product of the other two zeroes is:
If x + 1 is a factor of 2x³ + ax² + 2bx + 1, and 2a – 3b = 4, then the value of a + 2b is:
The solution of the pair of equations and x + y = 2ab is:
If the roots of the equation x³ − 12x² + 39x − 28 = 0 are in A.P., then their common difference is:
Both the roots of the equation (x − a)(x − b) + (x − b)(x − c) + (x − c)(x − a) = 0 are always:
The value of ‘a’ for which one root of the quadratic equation (a² − 5a + 3)x² + (3a − 1)x + 2 = 0 is twice the other, is:
Simplify:
Find roots of 5m² + 18m + 16 = 0
Find roots of 4m² + 6m + 2 = 0
If sum and product of the roots of a quadratic equation are and –28, respectively, then find the quadratic equation.
Suggested Test Series
Suggested Test Series
