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    What is the HCF of (t²-3t-4), (t²+5t-4), (t²-1)?
    Question

    What is the HCF of (t²-3t-4), (t²+5t-4), (t²-1)?

    A.

    t² - 1

    B.

    t² + 1

    C.

    t - 1

    D.

    1

    Correct option is D

    Solution: 

    (t2^2-3t - 4) = (t2^2-4t+t-4) = (t-4) (t + 1) ​

    (t2^2 + 5t - 4) = (t2^2 + 4t+t-4) = (t -1) (t+4)

    (t2^2-1) = (t + 1)(t - 1)

    As nothing is common

    Thus, HCF is 1

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