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What is the HCF of (t²-3t-4), (t²+5t-4), (t²-1)?
Question

What is the HCF of (t²-3t-4), (t²+5t-4), (t²-1)?

A.

t² - 1

B.

t² + 1

C.

t - 1

D.

1

Correct option is D

Solution: 

(t2^2-3t - 4) = (t2^2-4t+t-4) = (t-4) (t + 1) ​

(t2^2 + 5t - 4) = (t2^2 + 4t+t-4) = (t -1) (t+4)

(t2^2-1) = (t + 1)(t - 1)

As nothing is common

Thus, HCF is 1

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