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What is the discriminant of the equation x² − 2x + 13 = 0? Also, determine how many real solutions this equation has.
Question

What is the discriminant of the equation x² − 2x + 13 = 0? Also, determine how many real solutions this equation has.

A.

44, Two real roots

B.

−48, No real roots

C.

40, Two equal roots

D.

46, One real root

Correct option is B

Given:

Quadratic equation: x22x+13=0x^2 - 2x + 13 = 0​​

Formula Used:
Discriminant D =b24ac= b^2 - 4ac​ for ax2+bx+c=0. ax^2 + bx + c = 0.​​

If D > 0: 2 distinct real roots

If D = 0: 1 real (repeated) root

If D < 0: 0 real roots (two non-real complex roots)

Solution:
Here a = 1, b = -2, c =13.
D =(2)24(1)(13)=452=48.= (-2)^2 - 4(1)(13) = 4 - 52 = -48.​​
Since D < 0, the equation has no real solutions (two complex conjugate solutions).

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