What are the roots of the quadratic equation $$21x^2 - 37 x - 28 = 0 ?$$​​

Correct option is C

Given:

​$$21x^2 - 37x - 28 = 0$$​​

Solution:

​$$21x^2 - 37x - 28 = 0\\ \ \\ 21x^2 - 49x+12x - 28 = 0\\ \ \\ 7x(3x-7)+4(3x-7) = 0 \\ \ \\ (7x+4)(3x-7) = 0 \\ \ \\ \implies x = \frac{-4}{7}, \ \ \ \frac{7}{3}$$​​