Two resistors $$R_1$$​ and $$R_2$$​ have their resistance values in the ratio of 3 : 5. When they are combined in series, their equivalent resistance is 24 Ω. The individual resistances $$R_1$$​ and $$R_2$$​, respectively, are:

Correct option is C

​$$\begin{aligned}&\textbf{Given Information:} \\&\text{Resistance ratio: } R_1 : R_2 = 3 : 5 \\&\text{Series equivalent resistance: } R_{eq} = 24\,\Omega \\\\&\text{Let the common factor be } x. \text{ Then:} \\&R_1 = 3x \\&R_2 = 5x \\\\&\text{For series connection:} \\&R_{eq} = R_1 + R_2 \\&\text{Substitute the known values:} \\&24 = 3x + 5x \\&8x = 24 \\&x = 3\end{aligned}$$

$$\begin{aligned}&\bullet~ R_1 = 3x = 3 \times 3 = 9\,\Omega \\&\bullet~ R_2 = 5x = 5 \times 3 = 15\,\Omega\end{aligned}$$​​​