The intercept of the y-axis for the graph between stopping potential versus frequency will give us:

Correct option is C

​$$\text{In the photoelectric effect, the graph of stopping potential } V_s \text{ versus frequency } \nu \text{ gives a straight line with the intercept on the y-axis representing the work function of the metal.} \\\text{This relationship is given by the Einstein photoelectric equation:} \\eV_s = h\nu - \phi \\\text{Where:} \\eV_s \text{ is the kinetic energy of the emitted electron (i.e., the stopping potential),} \\h\nu \text{ is the energy of the incident photons,} \\\phi \text{ is the work function of the metal.} \\\text{Thus, the intercept on the y-axis of the } V_s \text{ vs. } \nu \text{ graph corresponds to the work function of the metal.}$$​​