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    The roots of the equation ax2+x+b=0ax^2 + x + b = 0ax2+x+b=0 are equal if:
    Question

    The roots of the equation ax2+x+b=0ax^2 + x + b = 0 are equal if:

    A.

    ab=14ab = \frac{1}{4}​​

    B.

    b2<4ab^2 < 4a​​

    C.

    b2>4ab^2 > 4a​​

    D.

    b2=4ab^2 = 4a​​

    Correct option is A

    Given:

    Given quadratic equation isax2+x+b=0 ax^2 + x + b = 0 ​​

    Formula Used:

    For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 ​​

    If roots are equal then determinant D = b24ac=0 b^2 - 4ac = 0​​

    Solution:

    For equationax2+x+b=0 ax^2 + x + b = 0 ​​

    a = a, b =1 and c = b

    Then putting the values in D

    We get,

    (1)24(a)(b)=0(1)^2 - 4(a)(b) = 0​​

    1=4abab=141 = 4ab\\ab = \frac{1}{4}

    Hence option(a) is correct

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