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The reaction of MoCl2 with [Et4N]Cl in dil. HCl and EtOH produces a dianionic hexanuclear metal cluster.A. The cluster is [Mo6Cl14]2-​B. The
Question

The reaction of MoCl2 with [Et4N]Cl in dil. HCl and EtOH produces a dianionic hexanuclear metal cluster.

A. The cluster is [Mo6Cl14]2-

​B. The cluster has 136 valence electrons

C. Each metal centre has 4 metal-metal bonds.

Identify the correct statement(s) about the cluster.

A.

B only

B.

A and C only

C.

B and C only

D.

A,B and C

Correct option is B

The structural formula is 

The Mo-Mo and Mo-Cl distances are about 2.60 and 2.47Å respectively. The six apical, terminal, Cl ligands lead to a quasi undeformed octahedral site (point group symmetry D3d) occupied by the M2+ cation.

When M is monovalent, two cations are to be inserted in the structure in order to counterbalance an 

anion. Such compounds have been obtained for Li, K, Cs and Cu.
These ternary molybdenum +II chlorides exhibit a diamagnetic behavior except in the case of 3d (V, Cr, Mn, Fe, Co, Ni) or Eu and Yb element compounds which show M2+ion paramagnetism (high spin configuration for 3d-cation compounds) : effectively, from molybdenum electronic state and anionic and cationic charge transfers, one can derive a number of 24 valency electrons per cluster corresponding to twelve two-electrons Mo-Mo bonds directed alongside the edges of the Mo6 octahedra.

6 Mo ([Kr] 4d⁵5s¹)=6×6=36

Chloride as a triply bridging (μ3) ligand donates five electrons=8×5=40

Chloride as a terminal ligand donates one electron=6×1=6

Total valence electrons=82

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