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    The product of the roots of 63x2+33+5x=06\sqrt{3}x^2 + 3\sqrt{3} + 5x = 063​x2+33​+5x=0​ is ___________.
    Question

    The product of the roots of 63x2+33+5x=06\sqrt{3}x^2 + 3\sqrt{3} + 5x = 0​ is ___________.

    A.

    12\frac{1}{2}​​

    B.

    11​​

    C.

    3\sqrt{3}​​

    D.

    0

    Correct option is A

    Given:

    Given expression 63x2+33+5x=06\sqrt{3}x^2 + 3\sqrt{3} + 5x = 0​​

    Formula Used:

    If α\alpha​ and β\beta​ are roots of equation ax2+bx+c=0ax^2 + bx +c =0​​

    Then sum of roots α+β=ba\alpha + \beta = -\frac{b}{a}​​

    Product of roots αβ=ca\alpha\beta = \frac{c}{a}​​

    Solution:

    The given expression can be written in standard form as : 63x2+5x+33=06\sqrt{3}x^2 + 5x+ 3\sqrt{3} = 0​​

    Then product of roots =3363=12 \frac{3\sqrt{3}}{6\sqrt{3}} = \frac{1}{2}​​

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