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The product of the roots of 63x2+33+5x=06\sqrt{3}x^2 + 3\sqrt{3} + 5x = 063​x2+33​+5x=0​ is ___________.
Question

The product of the roots of 63x2+33+5x=06\sqrt{3}x^2 + 3\sqrt{3} + 5x = 0​ is ___________.

A.

12\frac{1}{2}​​

B.

11​​

C.

3\sqrt{3}​​

D.

0

Correct option is A

Given:

Given expression 63x2+33+5x=06\sqrt{3}x^2 + 3\sqrt{3} + 5x = 0​​

Formula Used:

If α\alpha​ and β\beta​ are roots of equation ax2+bx+c=0ax^2 + bx +c =0​​

Then sum of roots α+β=ba\alpha + \beta = -\frac{b}{a}​​

Product of roots αβ=ca\alpha\beta = \frac{c}{a}​​

Solution:

The given expression can be written in standard form as : 63x2+5x+33=06\sqrt{3}x^2 + 5x+ 3\sqrt{3} = 0​​

Then product of roots =3363=12 \frac{3\sqrt{3}}{6\sqrt{3}} = \frac{1}{2}​​

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