The product of the roots of $$3x^2-13x+6=0$$​ is: 

The quadratic equation is $$3x^2−13x+6=0$$​​

For a quadratic equation of the form $$ax^2+bx+c=0,$$​ the product of the roots α and β is given by:

​$$α⋅β = \frac{c}{a}$$​​

where a is the coefficient of $$x^2$$​ and c is the constant term.

Identify a and c from the equation $$3x^2−13x+6=0:$$​​

a = 3, c = 6

Substitute the values into the formula:

​$$α⋅β = \frac{6}{3} =2$$​​

Thus, The product of the roots of the equation $$3x^2−13x+6=0$$​ is 2.