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    ​The graph below shows the plot of 1/v vs 1/[S] for an enzymatic reaction, with the solid and dashed lines representing the reactions without and with
    Question

    The graph below shows the plot of 1/v vs 1/[S] for an enzymatic reaction, with the solid and dashed lines representing the reactions without and with an inhibitor, respectively. The concentration of the inhibitor is 1 μM.

    Which one of the following will be theKlK_l of the inhibitor?

    A.

    0.33

    B.

    1.0

    C.

    0.50

    D.

    2.0

    Correct option is C

    The Lineweaver-Burk plot shows that the inhibitor increases the slope while keeping the y-intercept the same , indicating competitive inhibition. For Competitive inhibitors: 

    slope = KmV(max)\frac{K_m}{V_(max)}(1 +IKi\frac{I}{K_i}​)​

    From the graph, the ratio of the slope ,(α\alpha ​) = 3 , meaning

    α=1+[I]Ki\alpha = 1 + \frac{[I]}{K_i}

    Given [I] = 1 µM

    1Ki\frac{1}{K_i} = 2

    Ki= 0.50 µM 

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