The equation can be written as:
Given:
Solution:
Split the middle term:
Group and factor:
x (2x+3) +2(2x+3) = 0
Now, factor out the common binomial factor
(2x+3) (x+2) = 0
The equation can be written as:
(2x+3)(x+2) = 0
Thus, correct option is (b)
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90 Mins English English100 Questions100 Marks90 Mins English English40 Questions30 Marks25 Mins EnglishIf one of the zeroes of a cubic polynomial x³ + ax² + bx + c is 1, then the product of the other two zeroes is:
If x + 1 is a factor of 2x³ + ax² + 2bx + 1, and 2a – 3b = 4, then the value of a + 2b is:
The solution of the pair of equations and x + y = 2ab is:
If the roots of the equation x³ − 12x² + 39x − 28 = 0 are in A.P., then their common difference is:
Both the roots of the equation (x − a)(x − b) + (x − b)(x − c) + (x − c)(x − a) = 0 are always:
The value of ‘a’ for which one root of the quadratic equation (a² − 5a + 3)x² + (3a − 1)x + 2 = 0 is twice the other, is:
Simplify:
Find roots of 5m² + 18m + 16 = 0
Find roots of 4m² + 6m + 2 = 0
If sum and product of the roots of a quadratic equation are and –28, respectively, then find the quadratic equation.
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