Solve: $$3(5x^2-7)-5(3x^2+2x-7)=-16$$​

Correct option is B

Given:

​$$3(5x^2-7)-5(3x^2+2x-7)=-16$$​​

Solution:

​$$3×5^2−3×7−5×3^2−5×2+5×7=−16$$

​​$$15^2−21−15^2−10+35=−16$$

-21 - 10x + 35 = -16

14 − 10 x = -16

−10x = −16 −14

−10x = − 30

x = $$\frac{-30}{-10}$$​​

x = 3

Thus, the value of x is 3