Sides of a triangle are 6 cm, 6 cm and 8 cm. What is its area?

Correct option is C

Given:
Sides a, b, and c of the triangle = 6 cm, 6 cm, and 8 cm
Formula Used:
​$$\text{Area of triangle} = \sqrt{s(s - a)(s - b)(s - c)} \\\text{Semi-Perimeter} = \frac{a + b + c}{2}$$​​
Solution:
​$$s = \frac{6 + 6 + 8}{2} = 10\ \text{cm} \\\text{Area} = \sqrt{10 \times (10 - 6) \times (10 - 6) \times (10 - 8)} \\= \sqrt{10 \times 4 \times 4 \times 2} = 8\sqrt{5}\ \text{cm}^2$$​​