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    A right triangle has sides 3, 4, and 5. A smaller triangle is drawn inside it with its vertices on the sides of the larger triangle, such that it is s
    Question

    A right triangle has sides 3, 4, and 5. A smaller triangle is drawn inside it with its vertices on the sides of the larger triangle, such that it is similar to the larger triangle. If its perimeter is 6, what is its area?

    A.

    1.5

    B.

    2.4

    C.

    3

    D.

    6

    Correct option is A

    Given :

    A right triangle with sides 3, 4, 5
    A smaller triangle is drawn inside it, similar to the larger triangle.
    Perimeter of smaller triangle = 6.

    Formula Used :

    Perimeter ratio = ratio of corresponding sides
    PsmallPlarge=k\frac{P_{\text{small}}}{P_{\text{large}}} = k​​

    Area ratio of similar triangles
    AsmallAlarge=k2\frac{A_{\text{small}}}{A_{\text{large}}} = k^2​​

    Area of right triangle
    Area=12×base×height\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}​​
    Solution :

    Perimeter of larger triangle
    3 + 4 + 5 = 12

    Scale factor
    k=612=12 = \frac{6}{12} = \frac{1}{2}​​

    Area of larger triangle
    Alarge=12×3×4=6A_{\text{large}} = \frac{1}{2} \times 3 \times 4 = 6​​

    Area of smaller triangle
    Asmall=k2×Alarge=(12)2×6=14×6=1.5A_{\text{small}} = k^2 \times A_{\text{large}} = \left(\frac{1}{2}\right)^2 \times 6 = \frac{1}{4} \times 6 = 1.5​​

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