The length of the base of a triangle is 2 cm more than the corresponding height. If the area of the triangle is 220 cm³, then find the length of the base of the triangle.

Correct option is B

​$$\textbf{Given:} \\\text{Area of the triangle} = 220 \\\text{Let height of the triangle} = x \text{ cm} \\\text{Then base of the triangle} = (x + 2) \text{ cm} \\\textbf{Formula Used:} \\\text{Area of a triangle} = \dfrac{1}{2} \times \text{Base} \times \text{Height} \\\textbf{Solution:} \\220 = \dfrac{1}{2} \times (x + 2) \times x \\440 = x(x + 2) \\440 = x^2 + 2x \\x^2 + 2x - 440 = 0 \\(x + 22)(x - 20) = 0 \\x = 20 \ (\text{reject } -22) \\\text{Height} = 20 \text{ cm} \\\text{Base} = x + 2 = 20 + 2 = 22 \text{ cm} \\$$​​