The sides of a triangle are 82 cm, 18 cm, and 80 cm. What is its area? (in cm²)

Correct option is D

Given:

Sides of triangle = 82 cm, 18 cm, 80 cm

Find area 

Formula Used:

Semi-perimeter:

s =$$\frac{a+b+c}{2}$$​​

Area of triangle = $$\sqrt{s(s-a)(s-b)(s-c)}$$​​

Solution:

s =$$\frac{82 + 18 + 80}{2} = \frac{180}{2}$$​ = 90

Area of triangle  = $$\sqrt{90(90-82)(90-18)(90-80)}$$​​

= $$\sqrt{90 \times 8 \times 72 \times 10}$$​​

= $$\sqrt{720 \times 720}$$​​

= 720 cm²