Sakshi and Komal together can complete a work in 10 days. Komal can complete the same work in 22 days. They started working together but Sakshi left the work after 3 days and Komal completed the remaining work alone. Find the total number of days in which the work is completed.

Correct option is B

Given:
Sakshi and Komal together can complete a work in 10 days.
Komal alone can complete the same work in 22 days.
Sakshi left work after 3 days.
Formula Used:
Work = Efficiency x Time.
Solution:​
Total work = LCM(10, 22) = 110 units
Efficiency of Sakshi and Komal together =$$\frac{110}{10}$$​ = 11
Efficiency of Komal = $$\frac{110}{22}$$​= 5
Work done by Sakshi and Komal in 3 days = 11 × 3 = 33 units
Remaining work = 110 - 33 = 77 units
Days taken by Komal to complete the remaining work =$$\frac{77}{5}$$​ days

Total number of days in which work is completed = 3 + $$\frac{77}{5}$$​ = $$\frac{92}{5}$$​ days.