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Jitesh and Kamal can complete a certain piece of work in 18 and 17 days, respectively,They started to work together, and after 5 days, Kamal left. In
Question

Jitesh and Kamal can complete a certain piece of work in 18 and 17 days, respectively,They started to work together, and after 5 days, Kamal left. In how many days will Jiteshcomplete the remaining work?

A.

2360308\frac{2360}{308}​​

B.

2355307\frac{2355}{307}​​

C.

2361306\frac{2361}{306}​​

D.

2358306\frac{2358}{306}​​

Correct option is D

Given:

Jitesh completes work in 18 days

Kamal completes work in 17 days

Both work together for 5 days, then Kamal leaves

Find days Jitesh needs to complete remaining work

Formula Used:

Work done = Rate × Time

Solution:

Work done by Jitesh in 1 day = 118 \frac{1}{18}​​

Work done by Kamal in 1 day = 117\frac{1}{17}​​

Work done together in 1 day = 118+117 \frac{1}{18} + \frac{1}{17}​​

=17+1818×17=35306 = \frac{17 + 18}{18 \times 17} = \frac{35}{306}​​

Work done in 5 days together:

=5×35306=175306= 5 \times \frac{35}{306} = \frac{175}{306}​​

Remaining work:

=1175306=306175306=131306= 1 - \frac{175}{306} = \frac{306 - 175}{306} = \frac{131}{306}​​

Time for Jitesh to finish remaining work:

=131306118= \frac{\frac{131}{306}}{\frac{1}{18}}​​

=131306×18= \frac{131}{306} \times 18​​

=131×18306= \frac{131 \times 18}{306}​​

=131×18306= \frac{131 \times 18}{306}​​

=2358306 days= \frac{2358}{306} \ days  

Alternate Solution: 

LCM of 18 and 17 = 306 units 

Jitesh’s rate = 30618\frac{306}{18}​ = 17 units/day

Kamal’s rate = 30617\frac{306}{17}​ = 18 units/day

Work done together in 1 day = 17 + 18 = 35 units

Work done in 5 days = 35×5 = 175 units

Remaining work = 306 - 175 = 131 units

Time for Jitesh to finish remaining work = \frac{131}{17} 

=2358306= \frac{2358}{306}​ days

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